Question

A bag contains 5 red and 3 green balls. Another bag contains 4 red and 6 green balls. If one ball is drawn from each bag . Find the probability that one ball is red and one is green ?

• A. 19/20
• B. 17/20
• C. 8/10
• D. 21/40
• E. 15/40

Answer 1

The correct option is D 21/40

We have,
Bag 1:
Red ball = 5
Green ball = 3
Bag 2:
Red ball = 4
Green ball = 6
Now, according to the question we will have to cases.
1. Probability of getting Red ball from bag 1 and green ball from bag 2 = (5/8) * (6/10) = 30/80
2. Probability of getting Green from bag 1 and Red from bag 2 = (3/8) * (4/10) = 12/80
Therefore, probability of getting Red and Green,
= (30/80) + (12/80) = 42/80 = 21/40.