Question

A bag contains $50p,25p$ and $10p$ coins in the ratio $5:9:4$ which amounts to Rs. $206$. Find the number of coins of each type in the given order.

• A. $200,360,160$
• B. $100,80,120$
• C. $40,80,160$
• D. $222,322,440$

Answer 1

The correct option is A $200,360,160$

Let the number of $50p,25p$ and $10p$ coins be $5x,9x$ and $4x$ respectively.
$\frac{5x}{2}+\frac{9x}{4}+\frac{4x}{10}$ $4$ = $206$
$\Rightarrow$ $103x=4120$ $\Rightarrow$ x = $40$
Number of $50p$ coins = $5x=5$ $\times$ $40=200$
Number of $25p$ coins = $9x=4$ $\times$ $40=360$
Number of $10p$ coins = $4x=4$ $\times$ $40=160.$