Question

A bag contains $6$ red balls, $8$ white balls, $5$ green balls, and $3$ black balls. One ball is drawn at random from the bag. Find the probability that the ball is not green?

Answer 1

Number of red balls $=6$

Number of white balls $=8$

Number of green balls $=5$

Number of black balls $=3$

Total number of balls $=6+8+5+3=22$

Probability of not green = Probability of getting red, white and black

$P\left(E\right)=\frac{Numberoffavourableoutcomes}{Numberofpossibleoutcomes}$

$=(6+8+3)/22$

$=17/22$

Hence the probability of not green is $17/22$.