Question

A bag contains $6$ red balls and $4$ green balls. Find the probability of selecting at random a green ball?

Answer 1

Finding the probability of selecting a green ball:

The event is selecting a ball at random.

The total number of balls is

$$\begin{gathered} Totalnumberofballs=RedBalls+GreenBalls \\ Totalnumberofballs=6+4 \\ Totalnumberofballs=10 \end{gathered}$$

Henceforth, there are $10$ balls placed in a bag.

So, the total number of outcomes is $10$.

There are $4$ green balls in the bag.

So, the number of favorable outcomes is $4$.

The formula for probability is,

$$\begin{gathered} \Rightarrow Probability=\frac{Numberoffavorableoutcomes}{Totalnumberofoutcomes} \\ \Rightarrow P\left(green\right)=\frac{4}{10} \\ \therefore P\left(green\right)=\frac{2}{5} \end{gathered}$$

Therefore, the probability of selecting green balls is $\frac{2}{5}$.