A bag contains $7$ black, $5$ red and $3$ white balls. A ball is drawn from the bag at random. Find the probability that the ball drawn is not black.

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Solution

Finding the probability that the ball drawn is not black:
The total number of balls present in the bag are $7 + 5 + 3 = 15$ .
The total number of balls that are not black and are present in the bag are $15 - 7 = 8$ .
So, the number of favorable outcomes is $8$ and the total number of outcomes is $15$ .
The formula for probability is given by
$P r o b a b i l i t y = \frac{N u m b e r o f f a v o r a b l e o u t c o m e s}{T o t a l n u m b e r o f o u t c o m e s}$
$\Rightarrow P (n o t b l a c k) = \frac{8}{15} ∴ P (n o t b l a c k) = \frac{8}{15}$
Therefore, the probability that the ball drawn is not black is $\frac{8}{15}$ .

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