Question

A bag contains five green marbles, three blue marbles, two red marbles, and two yellow marbles. One marble is drawn out randomly.
a) Are the four different colour outcomes equally likely? Explain.
b) Find the probability of drawing each colour marble
i.e., P(green), P(blue), P(red) and P(yellow)
c) Find the sum of their probabilities.

Answer 1

Given in a bag contains five green marbles, three blue marbles, two red marbles and two yellow marbles

(a)The four colour out comes not equally because the number of four colours balls are different.

(b) Total ball $=5+3+2+1=11$

Then probability (green) $=$ $\frac{5}{11}$

Then probability (blue) $=$ $\frac{3}{11}$

Then probability (red) $=$ $\frac{2}{11}$

Then probability (yellow) $=$ $\frac{1}{13}$

(c) The sum of probabiilites $=$ $\frac{5}{11}+\frac{3}{11}+\frac{2}{11}+\frac{1}{11}=\frac{11}{11}=1$