A bag contains red, blue and green balls. It is twice as likely to pick a blue ball as compared to a red ball, and it is thrice as likely to pick a green ball as compared to a red ball. What is the probability of picking a green ball?

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Solution

Let P (Red) = x
Then, P (Blue) = 2x and P (Green) = 3x
x + 2x + 3x = 1 (Because the sum of probabilities of all outcomes is 1)
x = $\frac{1}{6}$ .
P (Green) = $\frac{3}{6}$ = $\frac{1}{2}$ .

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A bag contains red, blue and green balls. It is twice as likely to pick a blue ball as compared to a red ball, and it is thrice as likely to pick a green ball as compared to a red ball. What is the probability of picking a green ball?

Let P (Red) = x Then, P (Blue) = 2x and P (Green) = 3x x + 2x + 3x = 1 (Because the sum of probabilities of all outcomes is 1) x = 16. P (Green) = 36 = 12.

Let P (Red) = x
Then, P (Blue) = 2x and P (Green) = 3x
x + 2x + 3x = 1 (Because the sum of probabilities of all outcomes is 1)
x = $\frac{1}{6}$ .
P (Green) = $\frac{3}{6}$ = $\frac{1}{2}$ .