Question

A bag contains red white and blue marbles The
probability of selecting a red marble is $\frac{2}{15}$ and that
of selecting a blue marble is $\frac{4}{15}$ The probability
of selecting a white marble is

• A. $\frac{13}{15}$
• B. $\frac{11}{15}$
• C. $\frac{3}{5}$
• D. $\frac{2}{5}$

Answer 1

The correct option is C $\frac{3}{5}$

P(white marble) = Total probability - [P(red marble) + P(blue marble)]
= 1-$[\frac{2}{15}+\frac{4}{15}]=1-\frac{6}{15}=\frac{9}{15}=\frac{3}{5}$