A bag contains some green white and pink beads The probability of taking out one green bead is 1/3 and that of picking up one pink bead is 1/4 If it is known that the box has 10 white beads how many beads were in the box initially?

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Solution

The correct option is A 24
P(green)=1/3
P(pink)=1/4
P(white bead)=1- $(\frac{1}{3} + \frac{1}{4}) = \frac{5}{12} = \frac{10}{24}$
$∴$ Total number of beads=24

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A bag contains some green white and pink beads The probability of taking out one green bead is 1/3 and that of picking up one pink bead is 1/4 If it is known that the box has 10 white beads how many beads were in the box initially?

The correct option is A 24P(green)=1/3P(pink)=1/4P(white bead)=1-(13+14)=512=1024∴ Total number of beads=24

The correct option is A 24
P(green)=1/3
P(pink)=1/4
P(white bead)=1- $(\frac{1}{3} + \frac{1}{4}) = \frac{5}{12} = \frac{10}{24}$
$∴$ Total number of beads=24