A bag contains three green, four blue and two orange marbles. If a marble is picked at random, then the probability that it is not an orange marble, is __________.

\frac{1}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{4}{9}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{7}{9}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{7}{9}$
Number of green balls $= 3$
Number of blue balls $= 4$
Number of orange balls $= 2$
$\Rightarrow$ Total number of balls $= 9$
Favourable cases of not picking an orange ball $= 9 - 2 = 7$

Probability of not picking an orange ball $= \frac{7}{9}$

Suggest Corrections

Similar questions

A bag contains three green marbles, four blue marbles, and two orange marbles. If a marble is picked at random, then the probability that it is not an orange marble is

Q. A bag contains

7

blue marbles, three red marbles, and two white marbles. If one marble is chosen at random from the bag, what is the probability that it will not be blue?

Q. A bag contains

6

blue and

4

green marbles. If a marble is drawn at random from the bag, the probability that the marble drawn is green, is ___________.

An urn contains 6 red, 4 blue and 3 green marbles. If 2 marbles are picked at random, then what is the probability that both the marbles are red?

Q. A box contains 10 green, 20 red, 30 Black and 40 orange marbles. One marble is drawn from the box at random. The probability that marble is neither green nor orange is

A bag contains three green, four blue and two orange marbles. If a marble is picked at random, then the probability that it is not an orange marble, is __________.

The correct option is D 79Number of green balls =3Number of blue balls =4Number of orange balls =2⇒ Total number of balls =9Favourable cases of not picking an orange ball =9−2=7Probability of not picking an orange ball =79

The correct option is D $\frac{7}{9}$
Number of green balls $= 3$
Number of blue balls $= 4$
Number of orange balls $= 2$
$\Rightarrow$ Total number of balls $= 9$
Favourable cases of not picking an orange ball $= 9 - 2 = 7$

Probability of not picking an orange ball $= \frac{7}{9}$