A bag contains $7$ blue marbles, three red marbles, and two white marbles. If one marble is chosen at random from the bag, what is the probability that it will not be blue?

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Solution

The number of ways we can choose a ball from a bag is $7 + 3 + 2 = 12$
The number of ways we can choose a ball such that it is not blue is $3 + 2 = 5$
The probability is $5 / 12$

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A bag contains 7 blue marbles, three red marbles, and two white marbles. If one marble is chosen at random from the bag, what is the probability that it will not be blue?

The number of ways we can choose a ball from a bag is 7+3+2=12The number of ways we can choose a ball such that it is not blue is 3+2=5The probability is 5/12

A bag contains $7$ blue marbles, three red marbles, and two white marbles. If one marble is chosen at random from the bag, what is the probability that it will not be blue?

The number of ways we can choose a ball from a bag is $7 + 3 + 2 = 12$
The number of ways we can choose a ball such that it is not blue is $3 + 2 = 5$
The probability is $5 / 12$