A bag contains three green marbles, four blue marbles and two orange marbles. If a marble is picked at random, then the probability that it is not an orange marble is

$\frac{1}{4}$

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$\frac{1}{3}$

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$\frac{4}{9}$

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$\frac{7}{9}$

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Solution

The correct option is D
$\frac{7}{9}$

P (Picking an orange marble) $= \frac{2}{9}$
$∴$ P (not picking an orange marble) $= 1 - \frac{2}{9} = \frac{7}{9}$

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A bag contains three green marbles, four blue marbles and two orange marbles. If a marble is picked at random, then the probability that it is not an orange marble is

The correct option is D 79 P (Picking an orange marble) =29 ∴ P (not picking an orange marble)=1−29=79

The correct option is D
$\frac{7}{9}$

P (Picking an orange marble) $= \frac{2}{9}$
$∴$ P (not picking an orange marble) $= 1 - \frac{2}{9} = \frac{7}{9}$