A box contains 3 blue marbles 2 blue marbles 2 white marbles and 4 red marbles, if a marble is taken out at random from the box what is the probability that it will be a white one ?

\frac{2}{9}

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\frac{1}{9}

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\frac{7}{9}

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None of these

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Solution

The correct option is A $\frac{2}{9}$
Total number of marbles =9
Number of white marble =2
$∴$ Required probability $= \frac{2}{9} .$

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Similar questions

A box contains 3 blue, 2 white and 4 red marbles. If a marble is drawn at random from the box, what is the probability that it will not be a white marble?
(a) $\frac{1}{3}$ (b) $\frac{4}{9}$ (c) $\frac{7}{9}$ (d) $\frac{2}{9}$

Q. Question 9 (i)
A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be red?

Q. A box contains 3 blue, 2 white and 4 red marbles. If a marbles. If a marble is drawn at random from the box, what is the probability that it will not be a white marble?
(a)

\frac{1}{3}

(b)

\frac{4}{9}

(c)

\frac{7}{9}

(d)

\frac{2}{9}

Q. A box contains

5

red marbles,

8

white marbles and

4

green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be (i) red ? (ii) white ? (iii) not green?

A box contains 3 blue marbles 2 blue marbles 2 white marbles and 4 red marbles, if a marble is taken out at random from the box what is the probability that it will be a white one ?

The correct option is A 29Total number of marbles =9 Number of white marble =2 ∴ Required probability =29.

The correct option is A $\frac{2}{9}$
Total number of marbles =9
Number of white marble =2
$∴$ Required probability $= \frac{2}{9} .$