The correct option is A 531.4μF
Here, Line voltage, VL=1100V
Line current, IL=80A
Power supplied, P=100kW
∴ power factor of the circuit,
cosϕ=P3VLIL
=100×103√3×1100×80=0.656 leading
Impedance of the load per phase,
Z=VphIph=VL√3I1
=1100√380=7.94Ω
Resistance of the load per phase,
R=Zcosϕ=7.94×0.656
=5.208Ω=5.21Ω
Reactance of the load per phase,
XC=√Z2−R2
=√(7.94)2−(5.21)2=5.99Ω
Capacitance of the load per phase,
C=12πfXC
12π×50×5.99=531.4μF