A ball A moving with a certain velocity collides,with another ball B of the same mads at rrsr.If the coefficient of restitution is e,the ratio of the velocities of A and B just after collision is
As no external force is not acting during the collision,we can apply,law of conservation of momentum.
Let,the 1st ball will move with a velocity of v and the 2nd one with x after the collision.
so, mu+mâ‹…0=mâ‹…v+mâ‹…x
or, v+x=u ...1
Now,coefficient of restitution in this case = x−vu−0=e (coefficient of restitution is defined as the ratio of relative velocity after the collision to relative veocity before the collision)
o, x−v=eu .... 2
solving, 1 & 2 we get,
x=u(e+1)2 and , v=u(1−e)2
So, v:x=(1−e):(1+e)