A ball at rest is dropped from the top of a mountain. What is the distance travelled by the ball in the first two seconds? ( Take acceleration due to gravity $g = 9.8 m s^{- 2}$ )

101.4 m

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19.6 m

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39.2 m

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78.4 m

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Solution

The correct option is B $19.6 m$
Let downward direction be positive.
Given:
The ball is at rest initially. So, initial velocity is: $u = 0$
Acceleration due to gravity: $g = + 9.8 m s^{- 2}$
Time of travel, $t = 2 s$
Let the distance travelled by ball $s$ .
From equation of motion,
$s = u t + \frac{1}{2} g t^{2}$
$s = 0 \times 2 + \frac{1}{2} \times 9.8 \times 2^{2}$
$s = 19.6 m$

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A ball at rest is dropped from the top of a mountain. What is the distance travelled by the ball in the first two seconds? ( Take acceleration due to gravity g=9.8ms−2)

The correct option is B 19.6mLet downward direction be positive. Given: The ball is at rest initially. So, initial velocity is: u=0 Acceleration due to gravity: g=+9.8ms−2 Time of travel, t=2s Let the distance travelled by ball s. From equation of motion, s=ut+12gt2 s=0×2+12×9.8×22 s=19.6m

A ball at rest is dropped from the top of a mountain. What is the distance travelled by the ball in the first two seconds? ( Take acceleration due to gravity $g = 9.8 m s^{- 2}$ )