Question

A ball dropped from height H, loses 50% of its energy on each collision with the ground. height to which the ball rises after second impact with ground is-

• A. H
• B. $\frac{3H}{4}$
• C. $\frac{H}{2}$
• D. $\frac{H}{4}$

Answer 1

The correct option is D $\frac{H}{4}$

We know that energy of an object at height $H=mgH$

So, energy of a ball after second collision $=mgH\left(\frac{1}{2}\right)\left(\frac{1}{2}\right)=\frac{mgH}{4}$

So, the height to which the ball rises after second impact with ground is $\frac{H}{4}$

Therefore, D is correct option.