a ball has a mass of 50g and is moving with velocity of 2m/s collides with another ball having mass 40g the second ball is moving with velocity of 1m/s in same direction. the velocity of first ball reduces to 1.5m/s what is velocity of first ball after collision?

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Solution

$From the conservation of momentum we know that m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2} \Rightarrow 0.05 \times 2 + 0.04 \times 1 = 0.05 \times 1.5 + 0.04 \times v_{2} \Rightarrow v_{2} = \frac{0.05 \times 2 + 0.04 \times 1 - 0.05 \times 1.5}{0.04} = 1.625 {ms}^{- 1}$

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