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If a ball of ...

Question

If a ball of mass $0.4 k g$ moving with a velocity of $3 m s^{- 1}$ collides elastically with another ball of mass $0.6 k g$ which is at rest,Their velocities after collision will be

A

V_{1} = 0.3 m s^{- 1}, V_{2} = 1.4 m s^{- 1}

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B

V_{1} = 2.4 m s^{- 1}, V_{2} = 0.6 m s^{- 1}

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C

V_{1} = 1.4 m s^{- 1}, V_{2} = 0.3 m s^{- 1}

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D

V_{1} = 1.2 m s^{- 1}, V_{2} = 1.2 m s^{- 1}

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Solution

The correct option is D $V_{1} = 1.2 m s^{- 1}, V_{2} = 1.2 m s^{- 1}$
Formula,

$m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}$

when bodies collide with each other their velocities will be equal as the ball is in rest.

$0.4 \times 3 + 0.6 \times 0 = v_{1} (0.4 + 0.6)$

$1.2 + 0 = v_{1} (1)$

$∴ v_{1} = v_{2} = 1.2 m s^{- 1}$

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