wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ball initially at rest falls from a height h=2.5 m. After collision with surface having value of coefficient of restitution e=0.6, it rebounds back. Find the rebound velocity of ball.


A
2 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4.2 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
11.66 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 4.2 m/s
Let the velocity of ball just before collision is u1 m/s.
We know that,
For free fall,
u1=2gh
u1=2×9.8×2.5=7 m/s
Let the velocity of ball after collision be v1 m/s.
We know that,
e=v2v1u1u2
Initial and final velocity of surface is zero
u2 & v2 are equal to zero.
e=0v170
v1=e×7
v1=0.6×7
v1=4.2 m/s
So, the rebound velocity of the ball is 4.2 m/s.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Realistic Collisions
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon