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Question

A ball initially at rest falls from a height h=2.5 m. After collision with surface having value of coefficient of restitution e=0.6, it rebounds back. Find the rebound velocity of ball.


A
2 m/s
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B
4.2 m/s
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C
6 m/s
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D
11.66 m/s
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Solution

The correct option is B 4.2 m/s
Let the velocity of ball just before collision is u1 m/s.
We know that,
For free fall,
u1=2gh
u1=2×9.8×2.5=7 m/s
Let the velocity of ball after collision be v1 m/s.
We know that,
e=v2v1u1u2
Initial and final velocity of surface is zero
u2 & v2 are equal to zero.
e=0v170
v1=e×7
v1=0.6×7
v1=4.2 m/s
So, the rebound velocity of the ball is 4.2 m/s.

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