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Question

A ball is dropped downwards, after 1 sec another ball is dropped downwards from the same point. What is the distance between them after 3 sec? (Take g=10ms−2)

A
20m
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B
25m
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C
50m
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D
9.8m
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Solution

The correct option is B 25m
Distance at a given time is given by equation,
S=ut+12at2
For first body, u1=0, S=S1,a=g, t1=3sec
S1=12g×9
For second body, u2=0, S=S2, a=g, t2=2sec
S2=12g×4
So difference between them after 3sec=S1S2
=12g×5
If g=10 m/s2 then S1S2=25m

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