A ball is dropped from a height of 10m. If 40% of its energy is lost on collision with the earth then after collision the ball will rebound to a height of
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Solution
Given that the ball is dropped from a height, h1=10m
Potential energy at h1=mgh1
Given g=10m/s2,h1=10m
Therefore the potential energy at h1=m×10×10
=100m J
On striking the ground level, the ball looses 40% of its initial energy:
i.e. (40100)×100m J
=40m J
The energy left on striking the ground =100m J - 40m J