1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A ball is held at rest in position A by two light cords. The horizontal cord is now cut and the ball swings to position B. What is the ratio of the tension in the cord at position B to that at position A originally?

A
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3/4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B 3/4FBD of ball at position ′A′: For equilibrium of ball: Tcos30∘=mg ∴T=2√3mg ... (i) and T1=Tsin30∘ ... (ii) FBD of ball at position ′B′: Applying equilibrium condition for ball along the length of the string T1=mgcos30∘=√32mg ... (iii) From eq (i) and (iii) ∴T1T=(√32mg)(2√3mg)=34

Suggest Corrections
29
Join BYJU'S Learning Program
Related Videos
What's with All the Tension in the Room?
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program