CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ball is held at rest in position A by two light cords. The horizontal cord is now cut and the ball swings to position B. What is the ratio of the tension in the cord at position B to that at position A originally?


A
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3/4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 3/4
FBD of ball at position A:


For equilibrium of ball:
Tcos30=mg
T=23mg ... (i)
and T1=Tsin30 ... (ii)

FBD of ball at position B:


Applying equilibrium condition for ball along the length of the string
T1=mgcos30=32mg ... (iii)

From eq (i) and (iii)
T1T=(32mg)(23mg)=34

flag
Suggest Corrections
thumbs-up
29
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What's with All the Tension in the Room?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon