A ball is moving with of velocity 2 m/s towards a heavy wall, the wall is also moving with a speed of 1 m/s towards the ball as shown in fig. Assuming collision to be elastic, find the velocity of the ball immediately after the collision.
A
2 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
6 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is D 4 m/s Answer is C. The speed of wall will not change after the collision. So. let v be the velocity of the ball after collision in the direction shown in figure. Since collision is elastic (e = 1), separation speed = approach speed or v - 1 = 2 + 1 or v = 4 m/s. Hence, the velocity of the ball immediately after the collision is 4 m/s.