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Standard XII

Physics

Collision Example II

A ball is pro...

Question

A ball is projected horizontally with a velocity of $5 m / s$ from the top of a building $19.6 m$ high. How long will the ball take to hit the ground

\sqrt{2}

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2

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\sqrt{3}

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Solution

The correct option is B $2$ s
A ball is projected horizontally with a velocity of $5 m / s$ from the top of a building $19.6 m$ high. How long will the ball take to hit the ground

The time taken to hit the ground is given by,
$T = \sqrt{\frac{2 H}{g}} = \sqrt{\frac{2 \times 19.6}{9.8}} = 2 s$

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A ball is projected horizontally with a velocity of 5m/s from the top of a building 19.6m high. How long will the ball take to hit the ground

The correct option is B 2 sA ball is projected horizontally with a velocity of 5m/s from the top of a building 19.6m high. How long will the ball take to hit the groundThe time taken to hit the ground is given by,T=√2Hg=√2×19.69.8=2s

A ball is projected horizontally with a velocity of $5 m / s$ from the top of a building $19.6 m$ high. How long will the ball take to hit the ground

The correct option is B $2$ s
A ball is projected horizontally with a velocity of $5 m / s$ from the top of a building $19.6 m$ high. How long will the ball take to hit the ground

The time taken to hit the ground is given by,
$T = \sqrt{\frac{2 H}{g}} = \sqrt{\frac{2 \times 19.6}{9.8}} = 2 s$