Question

A ball is projected toward right from point A, at an angle $\theta$ with vertical. Due to air the ball experience a horizontal acceleration $gtan\theta$ towards left. Then ball will land on:

• A. Point A
• B. Point B
• C. Point C
• D. Information is not sufficient

Answer 1

Answer: (A)

Point A

$a_X=-g\tan \theta i$

$u_X=V\sin \theta i$

$u_Y=V\cos \theta \hat{j}$

$a_Y=-g\hat{j}$

$x=u_{X}t+\frac{1}{2}{a}_X{t}^2$

$=V\sin \theta .T-\frac{1}{2}g\tan \theta .T^2$

$T=\frac{2u_X}{g}=\frac{2V\cos \theta }{g}$

$x=V\sin \theta \times \frac{2V\cos \theta }{g}-\frac{1}{2}g\frac{\sin \theta }{\cos \theta }.\frac{4V^2{\cos }^2\theta }{g}$

$=\frac{V^2\sin 2\theta }{g}-\frac{V^2\sin 2\theta }{g}$

$x=0$

Point A