Question

A ball is released from a height of $200\text{m}$ with a velocity of $10\text{m/s}$. Find the landing velocity of the ball. [Take $g=10{\text{m/s}}^2$]

• A. $\sqrt{410}\text{m/s}$
• B. $10\sqrt{41}\text{m/s}$
• C. $100\sqrt{41}\text{m/s}$
• D. $10\sqrt{410}\text{m/s}$

Answer 1

The correct option is B $10\sqrt{41}\text{m/s}$

Given, initial or release velocity $u=10\text{m/s}$
height from where ball is released $h=200\text{m}$
So, landing velocity is given by
$v^2=u^2+2gh\Rightarrow v^2={10}^2+2\times 10\times 200$
$\Rightarrow v^2=4100\Rightarrow v=\sqrt{4100}=10\sqrt{41}\text{m/s}$