A ball is rolled off the edge of a horizontal table at a speed of 4 m/second. It hits the ground after 0.4 second. Which statement given below is true
Height of the table is 0.8 m
Vertical component of velocity of ball at point P.
vV = 0 + gt = 10 × 0.4 = 4m/s
Horizontal component of velocity = initial velocity
⇒vH = 4m/s
So the speed with which it hits the ground
v=√v2H+v2V=4√2 m/s and tan θ=vVvH=44=1⇒θ=45o
It means the ball hits the ground at an angle of 45o to the horizontal.
Height of the table h=12gt2=12×10×(0.4)2=0.8m
Horizontal distance travelled by the ball from the edge of table h = ut = 4 × 0.4 = 1.6m