You visited us 13 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Quantitative Aptitude

Progressions

A ball is thr...

Question

A ball is thrown from the ground such that its height $h$ varies with time as $h (t) = 16 t^{2} + 128 t$ . What is the height of the ball after $5$ seconds?

0

feet

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8

feet

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1040

feet

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

480

feet

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $1040$ feet
$h (t) = 16 t^{2} + 128 t$
$t = 5$ seconds $\Rightarrow h (5) = 16 (5)^{2} + 128 (5)$
$h (5) = 400 + 640 = 1040$ feet

Suggest Corrections

Similar questions

Q. A ball is throw into the air from an initial height of

10

feet. Its height above the ground, in feet,

t

seconds after it is thrown is given by the function

h (t) = 16 t^{2} + 27 t - 10

. How long will it take (in seconds) for the ball to hit the ground after it is thrown?

Q. The height

h

above the ground level reached by a ball ,

t

seconds after it is thrown is given by

h (t) = - 16 t^{2} + 46 t + 5

. Calculate the approximate maximum height the ball reaches. (All lengths in feet)

h = - 16 t^{2} + v t + k

The equation above gives the height

h

, in feet, of a ball

t

seconds after it is thrown straight up with an initial speed of

v

feet per second from a height of

k

feet. Which of the following gives

v

in terms of

h, t

and

k

Q. An object thrown upward from a height of

h

feet with an initial velocity of

v

feet per second will reach a maximum height of

h + \frac{v^{2}}{64}

feet.

If the object is thrown upward from a height of

6

feet with an initial velocity of

32

feet per second, what will be its maximum height, in feet?

During a practice match, a softball pitcher throws a ball whose height can be modeled by the equation $h = - 16 t^{2} + 24 t + 1$ , where h = height in feet and t = time in seconds. How long does it take for the ball to reach a height of 6 feet?

Join BYJU'S Learning Program

A ball is thrown from the ground such that its height h varies with time as h(t)=16t2+128t. What is the height of the ball after 5 seconds?

The correct option is C 1040 feeth(t)=16t2+128tt=5 seconds ⇒h(5)=16(5)2+128(5)h(5)=400+640=1040 feet

A ball is thrown from the ground such that its height $h$ varies with time as $h (t) = 16 t^{2} + 128 t$ . What is the height of the ball after $5$ seconds?

The correct option is C $1040$ feet
$h (t) = 16 t^{2} + 128 t$
$t = 5$ seconds $\Rightarrow h (5) = 16 (5)^{2} + 128 (5)$
$h (5) = 400 + 640 = 1040$ feet