A ball is thrown up under gravity $(g = 10 m / s e c^{2})$ . Finbd its velocity after $1.0$ sec at a height of $10 m$

5 m / s e c^{2}

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5 m / s e c

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10 m / s e c

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15 m / s e c

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Solution

The correct option is D $15 m / s e c$
Given,
$h = 10 m$
$t = 1 s e c$
$g = 10 m / s^{2}$
From the 2nd equation of motion,
$h = u t - \frac{1}{2} g t^{2}$
$10 = u \times 1 - \frac{1}{2} \times 10 \times 1 \times 1$
$u = 15 m / s$
The correct option is D.

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