A ball is thrown upwards with a velocity of 10 m/s. Find the maximum height reached by the ball.
Assume acceleration due to gravity $g = 10 m / s^{2}$ .

13 m

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5 m

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15 m

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16 m

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Solution

The correct option is B
5 m

Let $s$ be the distance covered.

Initail velocity $u = 10 m / s$

Since acceleration due to gravity is opposite to the direction of motion.
acceleration $a = - g = - 10 m / s^{2}$

At maximum height, velocity will be zero.
final velocity $v = 0$

Using the equation of motion
$v^{2} = u^{2} + 2 a s$
$0 = 100 + 2 \times - 10 \times s$
$s = 5 m$

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A ball is thrown upwards with a velocity of 10 m/s. Find the maximum height reached by the ball. Assume acceleration due to gravity g=10m/s2.

A ball is thrown upwards with a velocity of 10 m/s. Find the maximum height reached by the ball.
Assume acceleration due to gravity $g = 10 m / s^{2}$ .