Question

A ball is thrown upwards with a velocity of $10m{s}^{-1}$. Find the maximum height reached by the ball.

• A. $16m$
• B. $13m$
• C. $5m$
• D. $15m$

Answer 1

The correct option is C $5m$

Given:
Initial velocity, $u=10m{s}^{-1}$

Acceleration due to gravity is: $g\approx -10m/s^2$
Upward direction is taken as positive.

At the highest point, velocity is zero as the ball reverses it's direction of motion.
$v=0m{s}^{-1}$.

Let the maximum height be $H$.

Using third equation of motion,
$v^2=u^2+2as$​​
$0^2={10}^2+2\times (-10)\times H$
$H=5m$