A ball is thrown upwards with a velocity of $10 m s^{- 1}$ . Find the maximum height reached by the ball. Take acceleration due to gravity $g = 10 {m s}^{- 2}$ .

$13 m$

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$5 m$

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$15 m$

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$16 m$

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Solution

The correct option is B
$5 m$

The acceleration due to gravity is opposite to the direction of motion. At the highest point of motion, ball reverses its direction of motion and falls downwards. Thus, at maximum height, velocity of ball becomes zero.

Final velocity, $v = 0$
Initial velocity, $u = 10 m s^{- 1}$
Acceleration due to gravity, $g = - 10 m s^{- 2}$
Take upward direction as positive.

Using equation of motion,
$v^{2}$ = $u^{2}$ + 2as
$0^{2} = 10^{2} + 2 \times (- 10) \times s$
$s = 5 m$

Therefore, maximum height reached by ball, $s = 5 m$ .

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A ball is thrown upwards with a velocity of 10 ms−1. Find the maximum height reached by the ball. Take acceleration due to gravity g=10 ms−2.

A ball is thrown upwards with a velocity of $10 m s^{- 1}$ . Find the maximum height reached by the ball. Take acceleration due to gravity $g = 10 {m s}^{- 2}$ .