A ball is thrown upwards with a velocity of $10 m s^{- 1}$ . Find the maximum height reached by the ball.

13 m

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5 m

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15 m

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16 m

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Solution

The correct option is B $5 m$
Given:
Initial velocity, $u = 10 m s^{- 1}$

Acceleration due to gravity is: $g \approx - 10 m / s^{2}$
Upward direction is taken as positive.

At the highest point, velocity is zero as the ball reverses it's direction of motion.
$v = 0 m s^{- 1}$ .

Let the maximum height be $H$ .

Using third equation of motion,
$v^{2} = u^{2} + 2 a s$
$0^{2} = 10^{2} + 2 \times (- 10) \times H$
$H = 5 m$

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