A ball is thrown vertically downward with a velocity $u$ from the top of a tower. It strikes the ground with a velocity $5 u$ . The time taken by the ball to reach the ground is given by

2.5 u

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\frac{2 u}{g}

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\frac{4 u}{g}

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5 u

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Solution

The correct option is C $\frac{4 u}{g}$
Using first equation of motion, we have
$v = u + a t$ ,
As $v = 5 u$ and $a = g$ , we have
$5 u = u + g t \Rightarrow 4 u = g t \Rightarrow t = \frac{4 u}{g}$

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A ball is thrown vertically downward with a velocity u from the top of a tower. It strikes the ground with a velocity 5u. The time taken by the ball to reach the ground is given by

The correct option is C 4ugUsing first equation of motion, we have v=u+at, As v=5u and a=g, we have 5u=u+gt⇒4u=gt⇒t=4ug

A ball is thrown vertically downward with a velocity $u$ from the top of a tower. It strikes the ground with a velocity $5 u$ . The time taken by the ball to reach the ground is given by

The correct option is C $\frac{4 u}{g}$
Using first equation of motion, we have
$v = u + a t$ ,
As $v = 5 u$ and $a = g$ , we have
$5 u = u + g t \Rightarrow 4 u = g t \Rightarrow t = \frac{4 u}{g}$