A ball is thrown vertically upwards with a velocity of $30 m s^{- 1}$ What will be the height reached by the body at the end of $4 s$ (consider $g$ $10 m s^{- 2}$ )?

$7.5 m$

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$3 m$

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$120 m$

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$40 m$

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Solution

The correct option is D
$40 m$

Step 1: Given data and formula used
$u = 30 m s^{- 1} t = 4 s; a = - g = - 10 m s^{- 2}$
Formula used:
$h = u t + \frac{1}{2} a t^{2}$
Step 2: Calculation of the height
$h = 30 \times 4 - \frac{1}{2} \times 10 \times 16 = 120 - 80 = 40 m$
Hence, the correct option is (d).

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A ball is thrown vertically upwards with a velocity of 30ms–1 What will be the height reached by the body at the end of 4s (consider g 10ms–2)?

The correct option is D 40mStep 1: Given data and formula used u=30ms–1t=4s;a=–g=–10ms–2Formula used:h=ut+12at2Step 2: Calculation of the heighth=30×4-12×10×16=120–80=40mHence, the correct option is (d).

A ball is thrown vertically upwards with a velocity of $30 m s^{- 1}$ What will be the height reached by the body at the end of $4 s$ (consider $g$ $10 m s^{- 2}$ )?