A ball is thrown with a velocity of 40m/s at an angle of 60° with the horizontal from a point A on the ground. A boy simultaneously starts from A to move a constant velocity v such that the ball is always overhead the boy. Then value of v is
A
10m/s
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B
20m/s
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C
30m/s
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D
40m/s
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Solution
The correct option is B20m/s Horizontal component of velocity of ball, Vh=40cos60°=20 m/s For ball to remain always overhead the boy, relative velocity of ball in horizontal direction w.r.t the boy i.e. (Vhb)should be zero. →Vhb=→Vh−→Vb 0=40cos60°−v⇒v=20m/s