wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ball is thrown with an initial velocity of 20ms−1. Find the time of flight by the body. (Take g=10ms−2)

A
4s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
7s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 4s
Let a be the acceleration of the ball, u be the initial velocity, v be the final velocity and t be the time taken.

Initially the ball was moving in the upward direction. At maximum height, velocity will be zero, (v = 0). At that point, the ball will change the direction of motion and fall downwards.
Since, acceleration due to gravity is opposite to motion, a=10ms2
From first equation of motion, v=u+a
0=20+(10)t
t=2s
Thus, the ball takes 2s to reach the top. Similarly to reach the ground from the top point is also 2s. Thus total time or time of flight is 4s.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Uniform Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon