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Question

A ball is thrown with an initial velocity of 20ms−1. Find the time of flight by the body. (Take g=10ms−2)

A
4s
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B
5s
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C
6s
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D
7s
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Solution

The correct option is A 4s
Let a be the acceleration of the ball, u be the initial velocity, v be the final velocity and t be the time taken.

Initially the ball was moving in the upward direction. At maximum height, velocity will be zero, (v = 0). At that point, the ball will change the direction of motion and fall downwards.
Since, acceleration due to gravity is opposite to motion, a=10ms2
From first equation of motion, v=u+a
0=20+(10)t
t=2s
Thus, the ball takes 2s to reach the top. Similarly to reach the ground from the top point is also 2s. Thus total time or time of flight is 4s.

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