Question

A ball is tossed straight up from the ground half way up it has a speed of $19\cdot 6m/s$. Find
(a) Initial velocity
(b) The maximum height reached
$[g=9\cdot 8m/s]$

Answer 1

Given that,

Velocity $=19.6m/s$

Now,

(a). The initial velocity is

$u=19.6m/s$

Now,

(b). The maximum height is

$h_{max}=\frac{u^2}{2\times g}$

$h_{max}=\frac{19.6\times 19.6}{2\times 9.8}$

$h_{max}=19.6m$

Hence, this is the required solution