A ball moving with a momentum of $5 kg m/s$ strikes against a wall at an angle of 45° and is reflected at the same angle. Calculate the change in momentum (in magnitude).

7.07 kg m/s

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14.04 kg m/s

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3.53 kg m/s

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28.08 kg m/s

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Solution

The correct option is A $7.07 kg m/s$
Let $_{1}$ and $_{2}$ be the initial and final momenta respectively of the ball.
Change in momentum $=_{2} -_{1} =_{2} + (-_{1}) = - - \to A B$
From the figure

$A B = \sqrt{P_{1}^{2} + P_{2}^{2}} = \sqrt{5^{2} + 5^{2}} {kg ms}^{- 1}$ or $A B = \sqrt{50} {kg ms}^{- 1} = 7.07 {kg ms}^{- 1}$

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A ball moving with a momentum of 5 kg m/s strikes against a wall at an angle of 45° and is reflected at the same angle. Calculate the change in momentum (in magnitude).

The correct option is A 7.07 kg m/sLet −→P1 and −→P2 be the initial and final momenta respectively of the ball. Change in momentum =−→P2−−→P1=−→P2+(−−→P1)=−−→AB From the figure AB=√P21+P22=√52+52 kg ms−1 or AB=√50 kg ms−1=7.07 kg ms−1

A ball moving with a momentum of $5 kg m/s$ strikes against a wall at an angle of 45° and is reflected at the same angle. Calculate the change in momentum (in magnitude).