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Question

A ball of heat capacity 10caloC1 is heated to a certain temperature and then transferred into a vessel containing water and having a total water equivalent of 200 g. The temperature of water and vessel rises from 10oCto40oC . Then find the initial temperature of the ball.

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Solution

Heatlost=Heatgained
10(θ40)=200(4010)
θ40=800200=600
θ=640oC

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