A ball of mass 0.2kg moves with a velocity of 20m/s and it stops in 0.1s, then the force on the ball is
A
40N
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B
20N
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C
4N
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D
2N
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Solution
The correct option is B40N F=ma=m(υ−ut)=−mut Substituting the values and neglecting the negative sign (because none of the options is negative) F=0.2×200.1=40N