A ball of mass 0.20 kg falls freely from a certain height and rebounds elastically with a speed of $40 m s^{- 1}$ . The change in momentum of the ball is :

4 k g m s^{- 1}

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8 k g m s^{- 1}

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16 k g m s^{- 1}

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40 k g m s^{- 1}

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Solution

The correct option is C $16 k g m s^{- 1}$
Change in momentum, $Δ p = - 2 m v$
$= 2 \times 0.2 \times 40 = 16 k g m s^{- 1}$ (magnitude)

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