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Standard XII

Physics

Superposition of Electric Fields

A ball of mas...

Question

A ball of mass $1 g$ carrying a charge $10^{- 8} C$ moves from a point A at potential $600 V$ to a point B at zero potential.The change in its KE is

- 6 \times 10^{- 6} e r g

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- 6 \times 10^{- 6} J

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6 \times 10^{- 6} J

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6 \times 10^{- 6} e r g

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Solution

The correct option is C $6 \times 10^{- 6} J$
As work is done by the field , KE of the body increases by
$K E = W = q (V_{A} - V_{B})$
$10^{- 10} (600 - 0)$
$6 \times 10^{- 6} j$

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A ball of mass 1g carrying a charge 10−8C moves from a point A at potential 600V to a point B at zero potential.The change in its KE is

The correct option is C 6×10−6JAs work is done by the field , KE of the body increases by KE=W=q(VA−VB)10−10(600−0)6×10−6j

A ball of mass $1 g$ carrying a charge $10^{- 8} C$ moves from a point A at potential $600 V$ to a point B at zero potential.The change in its KE is

The correct option is C $6 \times 10^{- 6} J$
As work is done by the field , KE of the body increases by
$K E = W = q (V_{A} - V_{B})$
$10^{- 10} (600 - 0)$
$6 \times 10^{- 6} j$