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Question

A ball of mass 1g and charge 108C moves from A, where potential is 600V, to B, where potential is 0. The velocity of the ball at B is 20cm/s. The velocity of the ball at point A must have been

A
16.8cm/s
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B
22.8cm/s
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C
228cm/s
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D
168cm/s
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Solution

The correct option is B 22.8cm/s
Given a ball of m=1g=103kg
charge on ball, q=108C
potential at A;vA=600v
potential at B;vB=0
velocity of ball at $ B;{ v }_{ B }=20cm/s
we have to find velocity of ball at A
ex.vA=?
so; we use conservation of energy,
change in kinetic energy= change in potential energy.
12m(vA2vB2)=Q(vAvB)12×103(vA2(0.2)2)=108×(6000)vA2(0.2)2=6×106+2×103=12×103vA2=12×103+4×103vA=22.8cms1
hence the answer is option (b)

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