Question

A ball of mass $1kg$ is at rest in position $P$ by means of two light strings $OP$ and $RP$. The string $RP$ is now cut and the ball swings to position $Q$. If $\theta ={45}^o$. Find the ratio of tensions in the strings in positions $OP$ (when $RP$ was not cut ) and $OQ$ (when $RP$ was cut). Take $g=10m/s^2$

• A. $5\sqrt{2}$
• B. $2$
• C. $3$
• D. $1.5$

Answer 1

The correct option is A $5\sqrt{2}$

In the given figure$:-$

therefore net force along $=OQ=0$

$\begin{array}{c}{T}_2=mg\cos \theta \\ T_2=1\times 10\frac{1}{\sqrt{2}}\\ =5\sqrt{2}N\end{array}$

Hence,

all option in incorrect$,$ correct answer is $5\sqrt{2}N.$