CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ball of mass 2 kg moving with velocity 3 m/s, collides with spring of natural length 2 m and force constant 144 N/m. What will be length of compressed spring?

A
2 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.65 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.5 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1.65 m
Energy of the spring-ball must me conserved.
12mv2=12kx2

On substituting values,
12×2(3)2=12×144(x)2

Solving for x we get, x=0.35m
So, length of the compressed spring =20.35=1.65m

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon