Question

A ball of mass 200g moving with a velocity of 25 m/s is struck by the batsman to return along the same path in opposite direction with the same speed . the collision of the ball with bat lasts for 0.5 sec find the impulse of the force and tge average force of impact

Answer 1

Dear Student,

Initial velocity= u
final velocity= -u

Change in momentum= m(u-(-u)) = 2mu

$$\begin{gathered} 2\times 0.2\times 25\Rightarrow 10Kg-m/s(N-s) \\ Force=Rateofchangeinmomentum \\ F=\frac{0.2\times 2\times 25}{0.5}\Rightarrow 20N \end{gathered}$$

Regards.